Exit() Does Not Work

[kcraighead]

I am using the exit() command in one of my scripts and it is being ignored. Any idea why this would be?

 

The exit() is within a function which is attempting to grab a value out of an array as follows:

 

>
function get_setup_fee($prod_id, $M_PRODS, $M_SETUP ) {

//figure out the location of the product_id in the array and get it's key
$keyz = array_search($prod_id,$M_PRODS);

// now we have the key we the use the same key against the setup fees to find the matching one
$setup_fee = $M_SETUP[$keyz];

echo "The keyz is: " . $keyz;
echo "The prod_id is: " . $prod_id;
echo "M_PRODS is: " . $M_PRODS;
echo "The setup_fee is: " . $setup_fee;
exit();

return $setup_fee;
}

 

The $setup_fee value being returned is wrong so I want to echo the values to the screen so I can figure out the issue with the code. However the script continues to run so I can't see what the values are. Any idea why this would be?

 

I read on another forum that in shared hosting it may be "something with either safe_mode being enabled, output buffering being enabled, or error_reporting being enabled.". Anyone know anything about that?

 

Thanks for the help!

 

 

Hi! I am the guy behind NetChimp, a web design company.

 

NetChimp offers Web Design York and Web Design Aberdeen plus SEO York and are known as a good Small Business Web Designer with a website packed with Good Web Design Examples.

Edited December 13, 2011 by kcraighead

[TCH-Dick]

Your function is just returning the value of $setup_fee and wouldn't pass along exit() to the rest of the script. Just temporarily add exit() directly after you echo the returned value of get_setup_fee().

[OJB]

You could also try changing all your 'echo' statements to error_log() function calls. Like so:

 

>
error_log('The keyz is:' . $keyz);
error_log('The prod_id is: ' . $prod_id);
error_log('M_PRODS is: ' . $M_PRODS);
error_log('The setup_fee is: ' . $setup_fee);

 

Then check your php error log to see what has been written to it.